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userChrome.css syntax/reference

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  • Last reply by XorUnison

XorUnison
XorUnison
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I have a surprisingly simple question that seems to be ridiculously hard to answer on my own.

Where can I get a full syntax/reference for the userChrome.css? I've spent now like a day of searching and all places talking about userChrome.css never mention a source for the object names

In other words where can I look up things such as ".tabbrowser-tab[pinned="true"]" myself, without having to ask every single time I want to make adjustments?

I have a surprisingly simple question that seems to be ridiculously hard to answer on my own. Where can I get a full syntax/reference for the userChrome.css? I've spent now like a day of searching and all places talking about userChrome.css never mention a source for the object names In other words where can I look up things such as ".tabbrowser-tab[pinned="true"]" myself, without having to ask every single time I want to make adjustments?

Chosen solution

You can use the browser toolbox to find the selectors yourself; this article has directions on how to use it.

There's also a really helpful website created by another member of this forum that has lots of resources for this: https://www.userchrome.org/ .

Read this answer in context 👍 3

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user1929
user1929
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Chosen Solution

You can use the browser toolbox to find the selectors yourself; this article has directions on how to use it.

There's also a really helpful website created by another member of this forum that has lots of resources for this: https://www.userchrome.org/ .

XorUnison
XorUnison Question owner
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user1929 said

There's also a really helpful website created by another member of this forum that has lots of resources for this: https://www.userchrome.org/ .

I had already seen this website, but it wasn't sufficient.

user1929 said

You can use the browser toolbox to find the selectors yourself; this article has directions on how to use it.

Ah, this is it. I was wondering if there was an equivalent for the webdesign tools but I wasn't able to find it. This solution is 100%. Thanks a ton.