Avatar for Username

Zoeken in Support

Vermijd ondersteuningsscams. We zullen u nooit vragen een telefoonnummer te bellen, er een sms naar te sturen of persoonlijke gegevens te delen. Meld verdachte activiteit met de optie ‘Misbruik melden’.

Meer info

Deze conversatie is gearchiveerd. Stel een nieuwe vraag als u hulp nodig hebt.

Filter: Require all recipients to be in an address book

  • 1 antwoord
  • 1 heeft dit probleem
  • 2 weergaven
  • Laatste antwoord van Gnospen

shipman
shipman
more options

I use Thunderbird 45.2.0 and an IMAP account. I would like to create a filter that checks whether the sender is in a specific address book and all recipients are in a (different) specific address book. Unfortunately Thunderbird seems to only check whether any recipient is in the specified address book. Is this the expected result? Can the described filter method be achieved?

Also: Is there are way (perhaps an add-on?) to use logical expressions (and/or/not) to combine filter rules?

I use Thunderbird 45.2.0 and an IMAP account. I would like to create a filter that checks whether the sender is in a specific address book and all recipients are in a (different) specific address book. Unfortunately Thunderbird seems to only check whether any recipient is in the specified address book. Is this the expected result? Can the described filter method be achieved? Also: Is there are way (perhaps an add-on?) to use logical expressions (and/or/not) to combine filter rules?

Alle antwoorden (1)

Gnospen
Gnospen
more options

A good help is FiltaQuilla With that you have options like is not in my address-book A + is not in my address-book B + .....C Add sender to address-book C

Look at msgFilterRules.dat under an account in your profile-directory and you see that filters are written as logical (and, or, not)

name="any of" enabled="no" type="17" action="Mark unread" condition="OR (subject,contains,me) OR (subject,contains,you)"

name="and-or-not" enabled="no" type="17" action="Mark unread" condition="AND (subject,begins with,new) AND (subject,doesn't contain,old) AND (subject,ends with,me)"