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how do I create a css entry via the console style editor

  • 2 antwoorden
  • 1 heeft dit probleem
  • 2 weergaven
  • Laatste antwoord van Kevin

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My choice for the visited link color isn't loading. I select Tools => Web Dev => Style Editor...five (5) .css files are present: Common-min.css, print-min.css, questions-min.css, jqueryui-min.css and tabzilla-min.css. I "imported" the file as a .css, named 'userContent.css'. I've followed the advice to create a "userContent.css" file, with the following: a:visited {

 color:#E52121 !important;	
 background-color:#E8E8E8;

} I then exit Firefox, restart Firefox. Check the Tools => Web Dev => Style Editor, for the new .css file. Nada, zip, nothing, the new .css file isn't listed. Therefore I have not done as I intended to do! Where did I go wrong?

My choice for the visited link color isn't loading. I select Tools => Web Dev => Style Editor...five (5) .css files are present: Common-min.css, print-min.css, questions-min.css, jqueryui-min.css and tabzilla-min.css. I "imported" the file as a .css, named 'userContent.css'. I've followed the advice to create a "userContent.css" file, with the following: a:visited { color:#E52121 !important; background-color:#E8E8E8; } I then exit Firefox, restart Firefox. Check the Tools => Web Dev => Style Editor, for the new .css file. Nada, zip, nothing, the new .css file isn't listed. Therefore I have not done as I intended to do! Where did I go wrong?

Alle antwoorden (2)

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In the Style editor you only see the CSS files used by the website in the currently selected tab.

You won't see any references to the userContent.css file via the built-in Inspector. Only the DOM Inspector show such CSS rules if you inspect an element that have a matching selector.

You do not need to import the userContent.css file as Firefox does this automatically each time you start Firefox and the rules that apply will automatically be added.


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The link visited isn't changing colors to #E8E8E8!